576=((16x)^2)+((9x)^2)

Solution for 576=((16x)^2)+((9x)^2) equation:

576=((16x)^2)+((9x)^2)

We move all terms to the left:

576-(((16x)^2)+((9x)^2))=0

determiningTheFunctionDomain
-(16x^2+9x^2)+576=0

We get rid of parentheses

-16x^2-9x^2+576=0

We add all the numbers together, and all the variables

-25x^2+576=0

a = -25; b = 0; c = +576;
Δ = b2-4ac
Δ = 02-4·(-25)·576
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*-25}=\frac{-240}{-50}
=4+4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*-25}=\frac{240}{-50}
=-4+4/5
$